Technical Information
Balanced Cutting
Balanced cutting occurs when both inserts are set to exactly the same height. This height balancing is much more important than diametral balancing. A slight difference in height, even that caused by the insert tolerance, can have a dramatic effect upon the tool’s performance. This is particularly true in the case of long chipping materials.
Example of unbalanced cut:
- Feed rate .016 IPR.
- Insert “A” is .003 higher than insert “B.” (The tolerance on an M style insert is .002-.004.)
- The material removed by insert “A” is .008” + .003” = .011”
- The material removed by insert “B” is .008” – .003” = .005”
- The chip taken by insert “A” is over twice as thick as that taken by insert “B”.
The difference in cutting forces caused by the differences in insert height illustrated above can have the following effects on the bar’s performance:
- Possible wobble or chatter; extra load on the machine tool;
- Generally, the bore diameter becomes larger than the set diameter;
- Uniform chip formation is not possible, making it difficult to break and clear chips.
| Bore Diameter Range | Insert Height | Cutting Diameter |
|---|---|---|
| .95 – 1.31 | .001 | .008 |
| 1.26 – 1.74 | .001 | .012 |
| 1.58 – 2.17 | .001 | .012 |
| 2.06 – 2.83 | .002 | .016 |
| 2.61 – 6.00 | .002 | .016 |
| 6.00+ | .002 | .020 |
